15x^2+95x-200=0

Solution for 15x^2+95x-200=0 equation:

15x^2+95x-200=0

a = 15; b = 95; c = -200;
Δ = b2-4ac
Δ = 952-4·15·(-200)
Δ = 21025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{21025}=145$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(95)-145}{2*15}=\frac{-240}{30}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(95)+145}{2*15}=\frac{50}{30}
=1+2/3
$